x+5=(x^2+x-2)/2

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Solution for x+5=(x^2+x-2)/2 equation: 


x in (-oo:+oo)

x+5 = (x^2+x-2)/2 // - (x^2+x-2)/2

x-((x^2+x-2)/2)+5 = 0

(-1*(x^2+x-2))/2+x+5 = 0

(-1*(x^2+x-2))/2+(2*x)/2+(2*5)/2 = 0

2*x-1*(x^2+x-2)+2*5 = 0

x-x^2+2+10 = 0

x-x^2+12 = 0

x-x^2+12 = 0

x-x^2+12 = 0

DELTA = 1^2-(-1*4*12)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(-1*2) or x = (-49^(1/2)-1)/(-1*2)

x = -3 or x = 4

(x+3)*(x-4) = 0

((x+3)*(x-4))/2 = 0

((x+3)*(x-4))/2 = 0 // * 2

(x+3)*(x-4) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -3, 4 }

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